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<title>Problem 1314. -- River过河 -- 衡阳八中OJ离线版-2012-02-29</title><center><h2>1314: River过河</h2><span class=green>Time Limit: </span>10 Sec&nbsp;&nbsp;<span class=green>Memory Limit: </span>162 MB<br><span class=green>Submit: </span>21&nbsp;&nbsp;<span class=green>Solved: </span>8<br>[<a href='submitpage.php?id=1314'>Submit</a>][<a href='problemstatus.php?id=1314'>Status</a>][<a href='bbs.php?id=1314'>Discuss</a>]</center><h2>Description</h2><div class=content>ZY带N个小Kid过河,小KID分成两种:高一年级,高二年级,由于存在代沟问题,如果同一条船上高一年级生和高二年级生数量之差超过K,就会发生不和谐的事件.当然如果一条船上全是同一年级的,就绝对不会发生争执.现在ZY按小KID队列的顺序依次安排上船,并且不能让他们在过河时发生争执.对于当前等待上船的小KID来说,要么让他上船,要么将停在渡口的船开走,再让他上另一条船,同一条船上的人不过超过M人.为了让所有的小KID过河,在知悉小KID队列的情况下,最少需要多少条船.
</div><h2>Input</h2><div class=content>第一行给出N,M,K.含义如上所述
下行N行用来描述小KID的队列,每行一个字符”A”或者”L”
</div><h2>Output</h2><div class=content>最少需要多少条船
</div><h2>Sample Input</h2>
			<div class=content><span class=sampledata>5 4 1<br />
A<br />
L<br />
L<br />
L<br />
A<br />
</span></div><h2>Sample Output</h2>
			<div class=content><span class=sampledata>2<br />
</span></div><h2>HINT</h2>
			<div class=content><p>前三个人一条船,后两个人一条船<br />
数据范围<br />
30% 数据中1<=N<=1000<br />
100%数据中1<=N<=250000,1<=M,K<=N<br />
</p></div><h2>Source</h2>
			<div class=content><p><a href='problemset.html?search='></a></p></div><center>[<a href='submitpage.php?id=1314'>Submit</a>][<a href='problemstatus.php?id=1314'>Status</a>][<a href='bbs.php?id=1314'>Discuss</a>]</center>﻿<br>

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